Tools · Bridges
Scour depth
Guided step by step as per IRC 78 and the IRS Bridge Substructure and Foundation Code: silt factor, regime width, normal and maximum scour depth, maximum scour level and the foundation level that gives enough grip.
Guided · step 1 of 8
What scour is and the data needed
During a flood the river picks up bed material and the bed drops, deepest at piers, abutments and bends. Foundations must go safely below the deepest scour. Lacey’s regime theory, adopted by IRC 78 and the IRS Bridge Substructure Code, gives the scour depth from the discharge, the waterway and the bed material.
Design discharge Q = 2000 m³/s; effective linear waterway W = 150 m
Bed material: mean size dₘ = 0.323 mm
HFL = 100 m, lowest bed = 94 m; code: IRC 78
River and bridge
Section at the pier
Waterway against regime width
Waterway narrower than regime: the flow is constricted and scour is worked out per metre of waterway.
Full solution, all steps at once
- What scour is and the data needed
Design discharge Q = 2000 m³/s; effective linear waterway W = 150 m
Bed material: mean size dₘ = 0.323 mm
HFL = 100 m, lowest bed = 94 m; code: IRC 78
- Discharge for scourQd = Q·(1 + increase)
Qd = 2000 × (1 + 30100) = 2600 m³/s
- Silt factorKsf = 1.76·√dm
Ksf = 1.76 × √0.323 = 1.76 × 0.5683 = 1
- Regime width: is the waterway restricted?Wr = 4.8·√Qd
Wr = 4.8 × √2600 = 244.75 m
W = 150 m is less than Wr: the waterway is restricted
- Normal scour depth (restricted waterway)Db = QdWdsm = 1.34·(Db²Ksf)1/3
Db = 2600150 = 17.333 m³/s per m
dsm = 1.34 × (17.333²1)1/3 = 1.34 × 6.697 = 8.974 m
(For comparison, the wide-river formula gives 6.504 m.)
- Maximum scour depthdmax = k·dsm
Right-angled bend, or at nose of piers: k = 2
dmax = 2 × 8.974 = 17.948 m below HFL
Straight reach: 1.27
Moderate bend: 1.5
Severe bend: 1.75
Right-angled bend, or at nose of piers: 2
- Maximum scour levelMSL = HFL − dmax
MSL = 100 − 17.948 = 82.052 m
That is 11.948 m below the lowest bed.
- Foundation level: grip below scourFoundation level ≤ MSL − dmax3
Grip = 0.333 × 17.948 = 5.983 m
Foundation level = 82.052 − 5.983 = 76.069 m (17.93 m below the bed)